First, find the slope of the given straight line by rearranging to
make the subject.
Therefore, the slope of this line is .
If the tangent is perpendicular to this line, then its slope will
Now find the slope function of the curve by differentiating
implicitly with respect to .
Next rearrange to make the subject.
Now set this slope function equal to and rearrange to give an
equation connecting and .
Now substitute this expression for into the equation of
the curve and solve for .
Finally, substitute back into the equation connecting and
and solve for .
Therefore, the point at which the tangent is perpendicular to the
given line is .