Find the equation of the normal to the curve at the point .
First, differentiate the function implicitly with respect to , using the product rule for the first term.
Now rearrange the equation to make the subject.
To find the slope at the point (1,4), substitute these values of and into the slope function.
If the slope of the tangent is , then the slope of the normal is (the negative reciprocal). Therefore,
the normal has a slope of and passes through the point (1,4). Its equation can be found using the general equation of a straight line.