If , determine .
We are given the equation . We can set up another
equation using the definition of a combination which is
Substituting for and 3 for , we have
Factoring the equation, the result is
The in the numerator and denominator
cancel each other other out. Cross multiply and the new equation is
Divided both sides by , and solve the resulting equation for .
The values of must be greater that 3, so . Substituting
this value into the original combination and solve.
The value of the combination is 10.