If where , and where , determine and the domain of .
The domain of is the intersection of the domains for and such that .
Recall that cannot be zero because real numbers are not divisible by zero.
The domain of is , as it is for all polynomial functions.
Likewise, the domain of is , as it is for all polynomial functions.
However, implies that .
So, the domain of such that is .
Therefore, the domain of is .
The formula for is found by dividing the formula for by .
In this case, and , so
Therefore, the solution is where .