Given that bisects , cm,
cm, and the area of ,
determine the area of approximated to the nearest two decimal places, if needed.
In and , corresponds to , corresponds to , and corresponds to . Also, side corresponds to side , side corresponds to side , and side corresponds to side . The ratio of to is . Also, since , the length of is , so the ratio of to is . Since , the SAS similarity theorem stipulates that and must be similar. Use the fact that the ratio of the areas of the surfaces of two similar triangles equals the square of the ratio of the lengths of any two corresponding sides of the triangles to find the area of .
Thus, the area of is .